std::is_assignable, std::is_trivially_assignable, std::is_nothrow_assignable - cppreference.com

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# std::is_assignable, std::is_trivially_assignable, std::is_nothrow_assignable

From cppreference.com
< cpp‎ | types

Defined in header `<type_traits>` |  |
template< class T, class U > struct is_assignable; | (1) | (since C++11)
template< class T, class U > struct is_trivially_assignable; | (2) | (since C++11)
template< class T, class U > struct is_nothrow_assignable; | (3) | (since C++11)

1) If the expression std::declval<T>() = std::declval<U>() is well-formed in unevaluated context, provides the member constant `value` equal true. For any other type, `value` is false.
2) same as (1), but evaluation of the assignment expression will not call any operation that is not trivial.
3) same as (1), but the evaluation of the assignment expression will not call any operation that is not noexcept.

## Inherited from std::integral_constant

### Member constants

value [static] | true if `T` is assignable from `U` , false otherwise (public static member constant)

### Member functions

operator bool | converts the object to bool, returns `value` (public member function)

### Member types

Type | Definition
`value_type` | `bool`
`type` | std::integral_constant<bool, value>

### [edit] Example

Run this code

    #include <iostream>
    #include <string>
    #include <type_traits>
    struct Ex1 { int n; };
    int main() {
        std::cout << std::boolalpha
                  << "int is assignable from int? "
                  << std::is_assignable<int, int>::value << '\n' // 1 = 1; wouldn't compile
                  << "int& is assignable from int? "
                  << std::is_assignable<int&, int>::value << '\n' // int a; a = 1; works
                  << "int is assignable from double? "
                  << std::is_assignable<int, double>::value << '\n'
                  << "int& is nothrow assignable from double? "
                  << std::is_nothrow_assignable<int&, double>::value << '\n'
                  << "string is assignable from double? "
                  << std::is_assignable<std::string, double>::value << '\n'
                  << "Ex1& is trivially assignable from const Ex1&? "
                  << std::is_trivially_assignable<Ex1&, const Ex1&>::value << '\n';
    }

Output:

    int is assignable from int? false
    int& is assignable from int? true
    int is assignable from double? false
    int& is nothrow assignable from double? true
    string is assignable from double? true
    Ex1& is trivially assignable from const Ex1&? true

### [edit] See also

is_copy_assignableis_trivially_copy_assignableis_nothrow_copy_assignable (C++11)(C++11)(C++11) | checks if a type has a copy assignment operator (class template) [edit]
is_move_assignableis_trivially_move_assignableis_nothrow_move_assignable (C++11)(C++11)(C++11) | checks if a type has a move assignment operator (class template) [edit]

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