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# Bit fields

From cppreference.com
< c‎ | language

Declares a member with explicit width, in bits. Adjacent bit field members may be packed to share and straddle the individual bytes.

A bit field declaration is a struct or union member declaration which uses the following declarator:

identifier(optional) `:` width |  |

identifier | - | the name of the bit field that is being declared. The name is optional: nameless bitfields introduce the specified number of bits of padding
width | - | an integer constant expression with a value greater or equal to zero and less or equal the number of bits in the underlying type. When greater than zero, this is the number of bits that this bit field will occupy. The value zero is only allowed for nameless bitfields and has special meaning: it specifies that the next bit field in the class definition will begin at an allocation unit's boundary.

### [edit] Explanation

Bit fields can have only one of four types (possibly const or volatile qualified):

- unsigned int, for unsigned bit fields (unsigned int b:3; has the range 0..7)
- signed int, for signed bit fields (signed int b:3; has the range -4..3)
- int, for bit fields with implementation-defined signedness (Note that this differs from the meaning of the keyword `int` everywhere else, where it means "signed int"). For example, int b:3; may have the range of values 0..7 or -4..3.
- _Bool, for single-bit bit fields (bool x:1; has the range 0..1 and implicit conversions to and from it follow the boolean conversion rules.

Additional implementation-defined types may be acceptable. It is also implementation-defined whether a bit field may have atomic type. (since C11) The number of bits in a bit field (width) sets the limit to the range of values it can hold:

Run this code

    #include <stdio.h>
    struct S {
     // three-bit unsigned field,
     // allowed values are 0...7
     unsigned int b : 3;
    };
    int main(void)
    {
        struct S s = {7};
        ++s.b; // unsigned overflow
        printf("%d\n", s.b); // output: 0
    }

Multiple adjacent bit fields are permitted to be (and usually are) packed together:

Run this code

    #include <stdio.h>
    struct S {
        // will usually occupy 4 bytes:
        // 5 bits: value of b1
        // 11 bits: unused
        // 6 bits: value of b2
        // 2 bits: value of b3
        // 8 bits: unused
        unsigned b1 : 5, : 11, b2 : 6, b3 : 2;
    };
    int main(void)
    {
        printf("%zu\n",sizeof(struct S)); // usually prints 4
    }

The special unnamed bit field of width zero breaks up padding: it specifies that the next bit field begins at the beginning of the next allocation unit:

Run this code

    #include <stdio.h>
    struct S {
        // will usually occupy 8 bytes:
        // 5 bits: value of b1
        // 27 bits: unused
        // 6 bits: value of b2
        // 15 bits: value of b3
        // 11 bits: unused
        unsigned b1 : 5;
        unsigned :0; // start a new unsigned int
        unsigned b2 : 6;
        unsigned b3 : 15;
    };
    int main(void)
    {
        printf("%zu\n", sizeof(struct S)); // usually prints 8
    }

Because bit fields do not necessarily begin at the beginning of a byte, address of a bit field cannot be taken. Pointers to bit fields are not possible. Bit fields cannot be used with sizeof and alignas (since C11)

### [edit] Notes

The following properties of bit fields are undefined:

- The effect of calling offsetof on a bit field

The following properties of bit fields are unspecified:

- Alignment of the allocation unit that holds a bit field

The following properties of bit fields are implementation-defined:

- Whether bit fields of type int are treated as signed or unsigned
- Whether types other than int, signed int, unsigned int, and _Bool are permitted
- Whether atomic types are permitted
- Whether a bit field can straddle an allocation unit boundary
- The order of bit fields within an allocation unit (on some platforms, bit fields are packed left-to-right, on others right-to-left)

Even though the number of bits in the object representation of `_Bool` is at least CHAR_BIT, the width of the bit field of type `_Bool` cannot be greater than 1.

In the C++ programming language, the width of a bit field can exceed the width of the underlying type.

### [edit] References

- C11 standard (ISO/IEC 9899:2011):

  - 6.7.2.1 Structure and union specifiers

- C99 standard (ISO/IEC 9899:1999):

  - 6.7.2.1 Structure and union specifiers

- C89/C90 standard (ISO/IEC 9899:1990):

  - 3.5.2.1 Structure and union specifiers

### [edit] See also

C++ documentation for Bit field

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