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# Member access operators

From cppreference.com
< cpp‎ | language

Accesses a member of its operand.

Operator name | Syntax | Over​load​able | Prototype examples (for class T)
--- | --- | --- | ---
Inside class definition | Outside class definition
subscript | `a[b]` | Yes | R& T::operator[](S b); | N/A
indirection | `*a` | Yes | R& T::operator*(); | R& operator*(T a);
address-of | `&a` | Yes | R* T::operator&(); | R* operator&(T a);
member of object | `a.b` | No | N/A | N/A
member of pointer | `a->b` | Yes | R* T::operator->(); | N/A
pointer to member of object | `a.*b` | No | N/A | N/A
pointer to member of pointer | `a->*b` | Yes | R& T::operator->*(S b); | R& operator->*(T a, S b);
Notes As with most user-defined overloads, return types should match return types provided by the built-in operators so that the user-defined operators can be used in the same manner as the built-ins. However, in a user-defined operator overload, any type can be used as return type (including void). One exception is `operator->`, which must return a pointer or another class with overloaded `operator->`.

### [edit] Explanation

Built-in subscript operator provides access to an object of function pointed-to by the pointer or array operand.

Built-in indirection operator provides access to an object or function pointed-to by the pointer operand.

Built-in address-of operator creates a pointer pointing to the object or function operand.

Member of object and pointer to member of object operators provide access to a member object or member function of the class operand.

Built-in member of pointer and pointer to member of pointer operators provide access to a member object or member function of the class pointed-to by the pointer operand.

#### [edit] Built-in subscript operator

For every object type `T` (possibly cv-qualified), the following function signature participates in overload resolution:

T& operator[](T*, std::ptrdiff_t); |  |
T& operator[](std::ptrdiff_t, T*); |  |

The non-pointer operand may be any expression of integral or unscoped enumeration type, it is implicitly converted to std::ptrdiff_t. The expression E1[E2] is exactly identical to the expression *(E1 + E2), that is, the pointer operand (which may be a result of array-to-pointer conversion, and which must point to an element of some array or one past the end) is adjusted to point to another element of the same array, following the rules of pointer arithmetics, and is then dereferenced.

When applied to an array, the subscript expression is an lvalue if the array is an lvalue, and an xvalue if it isn't (since C++11). When applied to a pointer, the subscript expression is always an lvalue.

The type `T` is not allowed to be an incomplete type, even if the size or internal structure of `T` is never used, as in &x[0].

Run this code

    #include <iostream>

    int main()
    {
        int a[4] = {1, 2, 3, 4};
        int* p = &a[2];
        std::cout << p[1] << p[-1] << 1[p] << (-1)[p] << '\n';
    }

Output:

    4242

#### [edit] Built-in indirection operator

For every type `T` that is either object type (possibly cv-qualified) or function type (not const- or ref-qualified), the following function signature participates in overload resolution:

T& operator*(T*); |  |

The operand of the built-in indirection operator is a pointer to object or function, and the result is the lvalue that the pointer is pointing to. Note that a pointer to incomplete type can be dereferenced, e.g. when initializing a reference.

Run this code

    #include <iostream>

    int f() { return 42; }

    int main()
    {
        int n = 1;
        int* pn = &n;

        int& r = *pn;  // lvalue can be bound to a reference
        int m = *pn;   // indirection + lvalue-to-rvalue conversion

        int (*fp)() = &f;
        int (&fr)() = *fp; // function lvalue can be bound to a reference
    }

#### [edit] Built-in address-of operator

The operand of the built-in `operator&` is either an lvalue expression of any type or the qualified name of a non-static member object or member function in some class. This operator does not participate in overload resolution. If there are no viable functions, special rules are used:

- If the operand is an lvalue expression of some type `T`, `operator&` creates and returns a prvalue of type `T*`, with the same cv qualification, that is pointing to the object designated by the operand. If the operand has incomplete type, the pointer can be formed, but if that incomplete type happens to be a class that defines its own `operator&`, the behavior is undefined (until C++14) it is unspecified whether the built-in or the overload is used (since C++14). For the operands of type with user-defined `operator&`, std::addressof may be used to obtain the true pointer.
- If the operand is the name of an overloaded function, the address may be taken only if the overload can be resolved due to context. See Address of an overloaded function for details.
- If the operand is a qualified name of a non-static member, e.g. &C::member, the result is a prvalue pointer to member function or pointer to member object of type `T` in class `C`. Note that neither &member nor C::member nor even &(C::member) may be used to initialize a pointer to member.

Run this code

    void f(int) {}
    void f(double) {}
    struct A { int i; };
    struct B { void f(); };

    int main()
    {
        int n = 1;
        int* pn = &n; // pointer
        int A::* mp = &A::i; // pointer to member object
        void (B::*mpf)() = &B::f; // pointer to member function

        void (*pf)(int) = &f; // overload resolution due to initialization context
    //  auto pf2 = &f; // error: ambiguous overloaded function type
        auto pf2 = static_cast<void (*)(int)>(&f); // overload resolution due to cast
    }

#### [edit] Built-in member access operators

The first operand of the `operator.` is an expression of complete class type `T`. The first operand of the built-in `operator->` is an expression of pointer to complete class type `T*`. The first operand of both operators is evaluated even if it is not necessary (e.g. when the second operand names a static member).

The second operand of both operators is a name of (formally, an id-expression that names) a member object or member function of `T` or of an unambiguous and accessible base class `B` of `T` (e.g. E1.E2 or E1->E2), optionally qualified (e.g. E1.B::E2 or E1->B::E2), optionally using template disambiguator (e.g. E1.template E2 or E1->template E2).

If a user-defined `operator->` is provided, the `operator->` is called again on the value that it returns, recursively, until an `operator->` is reached that returns a plain pointer. After that, built-in semantics are applied to that pointer.

The expression E1->E2 is exactly equivalent to (*E1).E2 for built-in types; that is why the following rules address only E1.E2.

In the expression E1.E2:

1) if `E2` is a static data member:

- if `E2` is of reference type `T&` or `T&&`, the result is an lvalue of type `T` designating the object or function to which `E2` refers,
- otherwise, the result is an lvalue designating that static data member.

  Essentially, `E1` is evaluated and discarded in both cases;

2) if `E2` is a non-static data member:

- if `E2` is of reference type `T&` or `T&&`, the result is an lvalue of type `T` designating the object or function to which `E2` refers,
- otherwise, if `E1` is an lvalue, the result is an lvalue designating that non-static data member of `E1`,
- otherwise (if `E1` is an rvalue), the result is an rvalue (until C++11)xvalue (since C++11) designating that non-static data member of `E1`.

  If `E2` is not a mutable member, the cv-qualification of the result is the union of the cv-qualifications of `E1` and `E2`, otherwise (if `E2` is a mutable member), it is the union of the volatile-qualifications of `E1` and `E2`;

3) if `E2` is a static member function, the result is an lvalue designating that static member function. Essentially, `E1` is evaluated and discarded in this case;
4) if `E2` is a non-static member function including a destructor, the result is a special kind of prvalue designating that non-static member function of `E1` that can only be used as the left-hand operand of a member function call operator, and for no other purpose;
5) if `E2` is a member enumerator, the result is a prvalue equal to that member enumerator of `E1`;
6) if `E2` is a nested type, the program is ill-formed (won't compile);
7) if `E1` is a scalar type and `E2` is a `~` followed by the type name or decltype specifier designating the same type (minus cv-qualifications), optionally qualified, the result is a special kind of prvalue that can only be used as the left-hand operand of a member function call operator, and for no other purpose. The function call operator is called pseudo destructor call operator, it takes no arguments, returns void, and performs no action other than initial evaluation of `E1`. This is the only case where the left-hand operand of `operator.` has non-class type. Allowing pseudo destructor call makes it possible to write code without having to know if a destructor exists for a given type.
Run this code

    #include <iostream>

    struct P
    {
        template<typename T>
        static T* ptr() noexcept { return new T; }
    };

    template<typename T>
    struct A
    {
        A(int n): n(n) {}
        int n;
        static int sn;
        int f() { return 10 + n; }
        static int sf() { return 4; }
        class B {};
        enum E {RED = 1, BLUE = 2};

        void g()
        {
            typedef int U;
            // keyword template needed for a dependent template member
            int* p = T().template ptr<U>();
            p->~U(); // U is int, calls int's pseudo destructor
            delete p;
        }
    };
    template<> int A<P>::sn = 2;

    int main()
    {
        A<P> a(1);
        std::cout << a.n << ' '
                  << a.sn << ' '   // A::sn also works
                  << a.f() << ' '
                  << a.sf() << ' ' // A::sf() also works
    //            << a.B << ' '    // error: nested type not allowed
                  << a.RED << ' '; // enumerator
    }

Output:

    1 2 11 4 1

#### [edit] Built-in pointer-to-member access operators

The first operand of the `operator.*` is an expression of class type `T`. The first operand of the `operator->*` is an expression of type pointer to class type `T*`.

The second operand of both operators is an expression of type pointer to member of `T` or pointer to member of an unambiguous and accessible base class `B` of `T`.

For every combination of types `D`, `B`, `R`, where class type `B` is either the same class as `D` or an unambiguous and accessible base class of `D`, and `R` is either an object or function type, the following function signature participates in overload resolution:

R& operator->*(D*, R B::*); |  |

where both operands may be cv-qualified, in which case the return type's cv-qualification is the union of the cv-qualification of the operands.

The expression E1->*E2 is exactly equivalent to (*E1).*E2 for built-in types; that is why the following rules address only E1.*E2.

In the expression E1.*E2:

1) if `E2` is a pointer to data member,

- if `E1` is an lvalue, the result is an lvalue designating that data member,
- otherwise (if `E1` is an rvalue), the result is an rvalue (until C++11)xvalue (since C++11) designating that data member;

2) if `E2` is a pointer to member function, the result is a special kind of prvalue designating that member function that can only be used as the left-hand operand of a member function call operator, and for no other purpose;
3) cv-qualification rules are the same as for member of object operator, with one additional rule: a pointer to member that refers to a mutable member cannot be used to modify that member in a const object;
4) if `E2` is a null pointer-to-member value, the behavior is undefined;
5) if the dynamic type of `E1` does not contain the member to which `E2` refers, the behavior is undefined;
6) if `E1` is an rvalue and `E2` points to a member function with ref-qualifier &, the program is ill-formed;
7) if `E1` is an lvalue and `E2` points to a member function with ref-qualifier &&, the program is ill-formed.
Run this code

    #include <iostream>

    struct S
    {
        S(int n): mi(n) {}
        mutable int mi;
        int f(int n) { return mi + n; }
    };

    struct D: public S
    {
        D(int n): S(n) {}
    };

    int main()
    {
        int S::* pmi = &S::mi;
        int (S::* pf)(int) = &S::f;

        const S s(7);
    //  s.*pmi = 10; // error: cannot modify through mutable
        std::cout << s.*pmi << '\n';

        D d(7); // base pointers work with derived object
        D* pd = &d;
        std::cout << (d.*pf)(7) << ' '
                  << (pd->*pf)(8) << '\n';
    }

Output:

    7
    14 15

### [edit] Standard library

Subscript operator is overloaded by many standard container classes

operator[] | accesses specific bit (public member function of `std::bitset`) [edit]
operator[] | provides indexed access to the managed array (public member function of `std::unique_ptr`) [edit]
operator[] | access specified character (public member function of `std::basic_string`) [edit]
operator[] | access specified element (public member function of `std::array`) [edit]
operator[] | access specified element (public member function of `std::deque`) [edit]
operator[] | access specified element (public member function of `std::vector`) [edit]
operator[] | access specified element (public member function of `std::map`) [edit]
operator[] | access specified element (public member function of `std::unordered_map`) [edit]
operator[] | accesses an element by index (public member function of `std::reverse_iterator`) [edit]
operator[] | accesses an element by index (public member function of `std::move_iterator`) [edit]
operator[] | get/set valarray element, slice, or mask (public member function of `std::valarray`) [edit]
operator[] | returns specified sub-match (public member function of `std::match_results`) [edit]

The indirection and member operators are overloaded by many iterators and smart pointer classes

operator*operator-> | dereferences pointer to the managed object (public member function of `std::unique_ptr`) [edit]
operator*operator-> | dereferences pointer to the managed object (public member function of `std::shared_ptr`) [edit]
operator*operator-> | accesses the managed object (public member function of `std::auto_ptr`) [edit]
operator* | dereferences the iterator (public member function of `std::raw_storage_iterator`) [edit]
operator*operator-> | dereferences the decremented underlying iterator (public member function of `std::reverse_iterator`) [edit]
operator* | no-op (public member function of `std::back_insert_iterator`) [edit]
operator* | no-op (public member function of `std::front_insert_iterator`) [edit]
operator* | no-op (public member function of `std::insert_iterator`) [edit]
operator*operator-> | accesses the pointed-to element (public member function of `std::move_iterator`) [edit]
operator*operator-> | returns the current element (public member function of `std::istream_iterator`) [edit]
operator* | no-op (public member function of `std::ostream_iterator`) [edit]
operator*operator-> (since C++11) | obtains a copy of the current character accesses a member of the current character, if `CharT` has members (public member function of `std::istreambuf_iterator`) [edit]
operator* | no-op (public member function of `std::ostreambuf_iterator`) [edit]
operator*operator-> | accesses the current match (public member function of `std::regex_iterator`) [edit]
operator*operator-> | accesses current submatch (public member function of `std::regex_token_iterator`) [edit]

No standard library classes overload `operator&` or `operator->*`. The best known example of overloaded `operator&` is the Microsoft COM class CComPtr. `operator->*` is sometimes overloaded by third-party custom smart pointers.

### [edit] Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR | Applied to | Behavior as published | Correct behavior
--- | --- | --- | ---
CWG 1213 | C++11 | subscripting an array rvalue resulted in lvalue | reclassified as xvalue

### [edit] See also

Operator precedence

Operator overloading

Common operators
assignment | increment decrement | arithmetic | logical | comparison | member access | other
a = b a += b a -= b a *= b a /= b a %= b a &= b a |= b a ^= b a <<= b a >>= b | ++a --a a++ a-- | +a -a a + b a - b a * b a / b a % b ~a a & b a | b a ^ b a << b a >> b | !a a && b a || b | a == b a != b a < b a > b a <= b a >= b | a[b] *a &a a->b a.b a->*b a.*b | a(...) a, b ? :
Special operators
`static_cast` converts one type to another related type `dynamic_cast` converts within inheritance hierarchies `const_cast` adds or removes cv qualifiers `reinterpret_cast` converts type to unrelated type C-style cast converts one type to another by a mix of `static_cast`, `const_cast`, and `reinterpret_cast` `new` allocates memory `delete` deallocates memory `sizeof` queries the size of a type `sizeof...` queries the size of a parameter pack (since C++11) `typeid` queries the type information of a type `noexcept` checks if an expression can throw an exception (since C++11) `alignof` queries alignment requirements of a type (since C++11)

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