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# Variadic arguments

From cppreference.com
< c‎ | language

Variadic functions are functions that may be called with different number of arguments.

Only new-style (prototyped) function declarations may be variadic. This is indicated by the parameter of the form ... which must appear last in the parameter list and must follow at least one named parameter.

    //New-style declaration
    int printx(const char* fmt, ...); // function declared this way
    printx("hello world"); // may be called with one
    printx("a=%d b=%d", a, b); // or more arguments

    // int printy(..., const char* fmt); // Error: ... must be the last
    // int printz(...); // Error: ... must follow at least one named parameter

At the function call, each argument that is a part of the variable argument list undergoes special implicit conversions known as default argument promotions.

Within the body of a function that uses variadic arguments, the values of these arguments may be accessed using the <stdarg.h> library facilities:

Defined in header `<stdarg.h>`
va_start | enables access to variadic function arguments (function macro) [edit]
va_arg | accesses the next variadic function argument (function macro) [edit]
va_copy (C99) | makes a copy of the variadic function arguments (function macro) [edit]
va_end | ends traversal of the variadic function arguments (function macro) [edit]
va_list | holds the information needed by va_start, va_arg, va_end, and va_copy (typedef) [edit]

### [edit] Notes

Although old-style (prototype-less) function declarations allow the subsequent function calls to use any number of arguments, they are not allowed to be variadic (as of C89). The definition of such function must specify a fixed number of parameters and cannot use the `stdarg.h` macros.

    //old-style declaration
    int printx(); // function declared this way
    printx("hello world"); // may be called with one
    printx("a=%d b=%d", a, b); // or more arguments
    // the behavior of one of these calls is undefined, depending on
    // whether the function is defined to take 1 or 3 parameters

### [edit] Example

Run this code

    #include <stdio.h>
    #include <time.h>
    #include <stdarg.h>

    void tlog(const char* fmt,...)
    {
        char msg[50];
        strftime(msg, sizeof msg, "%T", localtime(&(time_t){time(NULL)}));
        printf("[%s] ", msg);
        va_list args;
        va_start(args, fmt);
        vprintf(fmt, args);
        va_end(args);
    }

    int main(void)
    {
       tlog("logging %d %d %d...\n", 1, 2, 3);
    }

Output:

    [10:21:38] logging 1 2 3...

### [edit] References

- C11 standard (ISO/IEC 9899:2011):

  - 6.7.6.3/9 Function declarators (including prototypes) (p: 133)

  - 7.16 Variable arguments <stdarg.h> (p: 269-272)

- C99 standard (ISO/IEC 9899:1999):

  - 6.7.5.3/9 Function declarators (including prototypes) (p: 119)

  - 7.15 Variable arguments <stdarg.h> (p: 249-252)

- C89/C90 standard (ISO/IEC 9899:1990):

  - 3.5.4.3/5 Function declarators (including prototypes)

  - 4.8 VARIABLE ARGUMENTS <stdarg.h>

### [edit] See also

C++ documentation for Variadic arguments

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