

/*
 * Copyright (c) 1998, 2004, Oracle and/or its affiliates. All rights reserved.
 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
 *
 * This code is free software; you can redistribute it and/or modify it
 * under the terms of the GNU General Public License version 2 only, as
 * published by the Free Software Foundation.  Oracle designates this
 * particular file as subject to the "Classpath" exception as provided
 * by Oracle in the LICENSE file that accompanied this code.
 *
 * This code is distributed in the hope that it will be useful, but WITHOUT
 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
 * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
 * version 2 for more details (a copy is included in the LICENSE file that
 * accompanied this code).
 *
 * You should have received a copy of the GNU General Public License version
 * 2 along with this work; if not, write to the Free Software Foundation,
 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
 *
 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
 * or visit www.oracle.com if you need additional information or have any
 * questions.
 */

/* __kernel_tan( x, y, k )
 * kernel tan function on [-pi/4, pi/4], pi/4 ~ 0.7854
 * Input x is assumed to be bounded by ~pi/4 in magnitude.
 * Input y is the tail of x.
 * Input k indicates whether tan (if k=1) or
 * -1/tan (if k= -1) is returned.
 *
 * Algorithm
 *      1. Since tan(-x) = -tan(x), we need only to consider positive x.
 *      2. if x < 2^-28 (hx<0x3e300000 0), return x with inexact if x!=0.
 *      3. tan(x) is approximated by a odd polynomial of degree 27 on
 *         [0,0.67434]
 *                               3             27
 *              tan(x) ~ x + T1*x + ... + T13*x
 *         where
 *
 *              |tan(x)         2     4            26   |     -59.2
 *              |----- - (1+T1*x +T2*x +.... +T13*x    )| <= 2
 *              |  x                                    |
 *
 *         Note: tan(x+y) = tan(x) + tan'(x)*y
 *                        ~ tan(x) + (1+x*x)*y
 *         Therefore, for better accuracy in computing tan(x+y), let
 *                   3      2      2       2       2
 *              r = x *(T2+x *(T3+x *(...+x *(T12+x *T13))))
 *         then
 *                                  3    2
 *              tan(x+y) = x + (T1*x + (x *(r+y)+y))
 *
 *      4. For x in [0.67434,pi/4],  let y = pi/4 - x, then
 *              tan(x) = tan(pi/4-y) = (1-tan(y))/(1+tan(y))
 *                     = 1 - 2*(tan(y) - (tan(y)^2)/(1+tan(y)))
 */

static partial class fdlibm
{
        static double __kernel_tan(double x, double y, int iy)
		{
			const double
one   =  1.00000000000000000000e+00, /* 0x3FF00000, 0x00000000 */
pio4  =  7.85398163397448278999e-01, /* 0x3FE921FB, 0x54442D18 */
pio4lo=  3.06161699786838301793e-17, /* 0x3C81A626, 0x33145C07 */
T_0_ =
  3.33333333333334091986e-01, /* 0x3FD55555, 0x55555563 */
T_1_ =
  1.33333333333201242699e-01, /* 0x3FC11111, 0x1110FE7A */
T_2_ =
  5.39682539762260521377e-02, /* 0x3FABA1BA, 0x1BB341FE */
T_3_ =
  2.18694882948595424599e-02, /* 0x3F9664F4, 0x8406D637 */
T_4_ =
  8.86323982359930005737e-03, /* 0x3F8226E3, 0xE96E8493 */
T_5_ =
  3.59207910759131235356e-03, /* 0x3F6D6D22, 0xC9560328 */
T_6_ =
  1.45620945432529025516e-03, /* 0x3F57DBC8, 0xFEE08315 */
T_7_ =
  5.88041240820264096874e-04, /* 0x3F4344D8, 0xF2F26501 */
T_8_ =
  2.46463134818469906812e-04, /* 0x3F3026F7, 0x1A8D1068 */
T_9_ =
  7.81794442939557092300e-05, /* 0x3F147E88, 0xA03792A6 */
T_10_ =
  7.14072491382608190305e-05, /* 0x3F12B80F, 0x32F0A7E9 */
T_11_ =
 -1.85586374855275456654e-05, /* 0xBEF375CB, 0xDB605373 */
T_12_ =
  2.59073051863633712884e-05; /* 0x3EFB2A70, 0x74BF7AD4 */

        double z,r,v,w,s;
        int ix,hx;
        hx = __HI(x);   /* high word of x */
        ix = hx&0x7fffffff;     /* high word of |x| */
        if(ix<0x3e300000) {                     /* x < 2**-28 */
          if((int)x==0) {                       /* generate inexact */
            if (((ix | __LO(x)) | (iy + 1)) == 0)
              return one / fabs(x);
            else {
              if (iy == 1)
                return x;
              else {    /* compute -1 / (x+y) carefully */
                double a, t;

                z = w = x + y;
                z = __LO(z, 0);
                v = y - (z - x);
                t = a = -one / w;
                t = __LO(t, 0);
                s = one + t * z;
                return t + a * (s + t * v);
                }
              }
          }
        }
        if(ix>=0x3FE59428) {                    /* |x|>=0.6744 */
            if(hx<0) {x = -x; y = -y;}
            z = pio4-x;
            w = pio4lo-y;
            x = z+w; y = 0.0;
        }
        z       =  x*x;
        w       =  z*z;
    /* Break x^5*(T[1]+x^2*T[2]+...) into
     *    x^5(T[1]+x^4*T[3]+...+x^20*T[11]) +
     *    x^5(x^2*(T[2]+x^4*T[4]+...+x^22*[T12]))
     */
        r = T_1_+w*(T_3_+w*(T_5_+w*(T_7_+w*(T_9_+w*T_11_))));
        v = z*(T_2_+w*(T_4_+w*(T_6_+w*(T_8_+w*(T_10_+w*T_12_)))));
        s = z*x;
        r = y + z*(s*(r+v)+y);
        r += T_0_*s;
        w = x+r;
        if(ix>=0x3FE59428) {
            v = (double)iy;
            return (double)(1-((hx>>30)&2))*(v-2.0*(x-(w*w/(w+v)-r)));
        }
        if(iy==1) return w;
        else {          /* if allow error up to 2 ulp,
                           simply return -1.0/(x+r) here */
     /*  compute -1.0/(x+r) accurately */
            double a,t;
            z  = w;
            z = __LO(z, 0);
            v  = r-(z - x);     /* z+v = r+x */
            t = a  = -1.0/w;    /* a = -1.0/w */
            t = __LO(t, 0);
            s  = 1.0+t*z;
            return t+a*(s+t*v);
        }
}
}
